A superheterodyne receiver having an IF of 9MHz is tuned to a frequency of 14.3MHz. The local oscillator frequency is greater than the signal frequency. The frequency of the local oscillator will be
The answer is :- 1
The local oscillator frequency can be either 23.3 MHz (14.3 MHz + 9 MHz) or 5.3 MHz (14.3 MHz - 9 MHz). But the local oscillator frequency is greater than the signal frequency, i.e. 23.3 MHz.
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