A superheterodyne receiver having an IF of 9MHz is tuned to a frequency of 14.3MHz. The local oscillator frequency is greater than the signal frequency.
The second channel (image) frequency will be
The answer is :- 4 A signal frequency of 14.3 MHz + (2 x 9) MHz, i.e. 32.3 MHz, will cause second channel interference, since this frequency less the local oscillator frequency (23.3 MHz) will give 9MHz.
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